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(C)=-0.02C^2+10C+768
We move all terms to the left:
(C)-(-0.02C^2+10C+768)=0
We get rid of parentheses
0.02C^2-10C+C-768=0
We add all the numbers together, and all the variables
0.02C^2-9C-768=0
a = 0.02; b = -9; c = -768;
Δ = b2-4ac
Δ = -92-4·0.02·(-768)
Δ = 142.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{142.44}}{2*0.02}=\frac{9-\sqrt{142.44}}{0.04} $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{142.44}}{2*0.02}=\frac{9+\sqrt{142.44}}{0.04} $
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